![]() ![]() The final step is to calculate the cross-sectional area of the conductor at the specified length of 150 ft.Ohm’s Law and Kirchhoff’s Voltage Law are very useful in circuit analysis. The next step is to calculate what voltage will be dropped across the conductor as it delivers current to the load. ![]() Since this is a resistive load the power factor will be unity or 100%. The first step is to calculate the current I 1. The final step is to use Ohm’s Law to solve for the voltage drop V L1across inductor L 1, and voltage drop V L2across inductor L 2.Įxample 5 is a voltage drop calculation with a 120V RMS source and a 1200W resistive load. ![]() Algebraically solving for I 1, we find the current. In this example we write one mesh equation around the loop in a clockwise direction, following the assumed direction of current flow for I 1. The final step is to use Ohm’s Law to solve for the voltage drop V L1across inductor L 1, and the voltage drop V L2across inductor L 2.Įxample 4 is the same ac circuit, only this time we will solve for the voltage drops using Kirchhoff’s Voltage Law (KVL). The next step is to use Ohm’s Law to calculate the current I 1. The next step is to calculate the total inductive reactance XL Tat the specified frequency of 60 Hz. The first step is to calculate the total inductance L T. The final step is to use Ohm’s Law to solve for the voltage drop V R1across resistor R 1, and the voltage drop V R2across resistor R 2.Įxample 3 is an AC circuit with a 12V RMS source and two series connected air core inductors L 1and L 2. KVL is maintained as the algebraic sum of the voltage drops 6V + 6V equals the voltage rise V 1of 12V.Įxample 2is the same dc resistive circuit, only this time we will solve for the voltage drops using Kirchhoff’s Voltage Law (KVL). You will note in the final answers that the voltage drop V R1is 6V, and the voltage drop V R2is 6V. The final step is to use Ohm’s Law again to solve for the voltage drop V R1across resistor R 1, and the voltage drop V R2across resistor R 2. The first step is to calculate the total resistance R T. Since it is a series circuit, you should note that the current I 1will be the same through each resistor Also note that the algebraic sum of the voltage drops should equal the voltage rise. Please note that the ac circuit calculations will contain only the magnitude and not the phase angle of the answer to keep things simple.Įxample 1 is a dc circuit with a 12-V source and two series connected resistors R 1and R 2. Examples 3 and 4 are ac circuit calculations involving inductors. Examples 1 and 2 are dc circuit calculations involving resistors. Illustrated here are five example calculations. The same network theorems that are used to evaluate resistive networks in dc circuit analysis can also be used to evaluate ac circuits that include resistors, inductors, and capacitors. AC circuit analysis is further broken down into single-phase and three-phase applications. Vector analysis is also very helpful as it allows for a graphical presentation of circuit characteristics. To allow for this simplification in the frequency domain the following criteria must be met: voltage and current sources must be sinusoidal in nature, and complex impedance must be expressed either in polar or rectangular notation. Usually the concepts of inductive reactance, capacitive reactance, and impedance simplify the circuit analysis in the frequency domain. AC circuit analysis is more complex and requires the use of calculus if the circuits are evaluated in the time domain. Once all the network theorems are discussed and evaluated, ac circuit analysis is introduced. In a typical engineering curriculum dc circuit analysis is introduced first with resistive networks. Electrical calculations generally fall within two categories: dc circuit analysis and ac circuit analysis. ![]()
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |